slicing.science.gmu.edu @ Wed Sep 14 15:36:47 1994
chochste@science
chochste@science tracing.science.gmu.edu @ Mon Sep 19 13:51:39 1994
Explain Keplar's law of planetary motion, ( if you increase the orbital radius of Earth to 2 AU's , the orbital period would be ?)
I do not know how to do this
jwallin@gmu.edu galileo.gmu.edu @ Tue Sep 20 17:46:46 1994
Kepler's Laws basically describe how planets move. The third law is a relationship between the
orbital distance and the orbital period. The equation is
Period^2 = (semi-major axis)^3. This means that if you have a planet with
an orbital radius of 2 AU, Period^2 = (2)^3. So, Period^2 = 8. If you take
the square root of both sides, you find that the period is the
square root of 8 years. The square root of 8 is about 2.8,
so the orbital period is about 2.8 years.
Hope this helped.
jw